12 months ago

Dhruv Agarwal • 0

/******************************************************************************

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               Code, Compile, Run and Debug C++ program online.
Write your code in this editor and press "Run" button to compile and execute it.

*******************************************************************************/

#include <iostream>
#include<bits/stdc++.h>
using namespace std;
int factor(vector<vector<int>>&a,int n,int m)
{
    int count=0;
    for(int i=0;i<n;i++)
    {
        int flag=0;
        for(int j=0;j<m;j++)
        {
            if(a[i][j]==0)
            {
                flag=1;
                break;
            }
        }
        if(flag==0)
        count++;
    }
    return count;
}
int maxfactor(vector<vector<int>>&a,int n,int m,int k,int col)
{
    if(k==0)
    {
        return factor(a,n,m);
    }
    if(col>=m)
    return 0;
    int temp=maxfactor(a,n,m,k,col+1);
    for(int i=0;i<n;i++)
    {
        a[i][col]=!a[i][col];
    }
    int temp2=maxfactor(a,n,m,k-1,col);
    for(int i=0;i<n;i++)
    {
        a[i][col]=!a[i][col];
    }
    return max(temp,temp2);
}
int main()
{
    int n,m,k;
    cin>>n>>m;
    vector<vector<int>>a(n,vector<int>(m));
    for(int i=0;i<n;i++)
    {
        for(int j=0;j<m;j++)
        {
            cin>>a[i][j];
        }
    }
    
    cin>>k;
    cout<<maxfactor(a,n,m,k,0);
    return 0;
}
 

10 months ago

Kshitiz Kumar • 0

Delhi

ll dp[21][21] ;
ll cal(ll j , ll n ,ll m , vector<vll>&arr, ll mask )
{

    if(j==m)
    {
        ll ans =0 ; 
        fl(i ,0 ,n )
        {
            ll f= 0;
            fl(j , 0, m )
            {
               if(mask&(1<<j))
               {
                 if(arr[i][j]>0)
                 {
                    f=1 ;
                    break ;
                 }
               }
               else
               {
                     if(arr[i][j]<0)
                 {
                    f=1 ;
                    break ;
                 }
               }
            }
            if(!f)
            ans++ ;
        }
        return ans ;
    }

    if(dp[j][mask]!=-1)
    return dp[j][mask]; 


    ll t=0 ,nt =0 ; 
    t = cal(j+1, n ,m , arr , mask|(1<<(j))) ;
    nt= cal(j+1, n , m, arr ,mask ) ;
   return dp[j][mask] = max(t, nt ) ;
}



void solve()
{

ll n ,m , k ;cin >> n>> m>> k ; 
vector<vll>arr(n , vll(m)) ;
fl(i ,0 ,n )
{
    fl(j ,0 , m)
    cin >> arr[i][j] ;
}
memset(dp , -1 ,sizeof(dp)) ;
cout << cal(0 , n , m ,arr , 0 ) ;

 
}

9 months ago

Yololo • 20

Rūpnagar

I think the simple logical explanation will be

1.) find all the similar rows. why?? (beacause only similar rows after applying ant operation to column will reflect similar changes);

2,) print(count of max(similar rows) if num zeroes<=k)

7 weeks ago

ADARSH RANJAN • 0

Jamshedpur

can u send all the questions