Answer: DraftKings SWE Interview Question 2024 September | Greedy | on-campus

Solution 1: Gas Station — Greedy One-Pass Algorithm Approach A brute-force solution checks all starting stations, taking O(N2) time. We can optimize this to O(N) using a **Greedy** approach based on two key insights: If the total sum of gas is greater than or equal to the total sum of cost: sum(gas) >= sum(cost), then a valid starting station is guaranteed to exist. If not, no solution exists, return -1. If we start at station A and fail to reach ...