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CITI Bank, Recent Online Assessment (30th August 2023) | Child's Parent
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Answer: ByteDance SDE OA 2025 | Viral Trend Analyzer & Optimal Video Encoding Schedule
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Solution - Viral Trend Analyzer Strategy A brute force approach computes the maximum for every window independently and requires O(N …
Answer: Airtel SDE OA 2025 | 5G Highway Coverage & Fiber Optic Grid Expansion
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Solution - 5G Highway Coverage Strategy This is a classic Merge Intervals problem. Since coordinates can be as large as 109, const…
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Solution - Suspicious Account Clusters Strategy This is a connected component problem. Since connections arrive dynamically and N can…
Answer: INNOVITI PAYMENTS Off-Campus OA (2021) | Problem Number of Arithmetic Triplets
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Padala Indira Bhavani
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Approach Store all numbers in a HashSet. For every number n: Check whether n - diff exists. Check whether n + diff exists. …
Answer: STELLAPPS On-Campus OA (2021) | Problem Check if All A's Appear Before All B's
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Approach Once a 'b' is encountered, no 'a' should appear afterwards. Use a boolean flag to track whether a 'b'…
Answer: ACKO INSURANCE Hiring | Maximum Difference Between Increasing Elements | Off-Cam
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Approach Maintain the smallest element seen so far while traversing the array. For every element: If it is greater than the min…
Answer: LEARNBAY On-Campus OA (2025) | Problem Merge Strings Alternately
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Padala Indira Bhavani
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Approach Use two pointers to traverse both strings simultaneously. Initialize pointers i and j at 0. Alternate characters from w…
Answer: ZUDDL Hiring Off-Campus OA (2025) | Problem Find the Difference of Two Arrays (
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Approach Use two HashSets to store distinct elements from both arrays. Insert all elements of nums1 into set1. Insert all elemen…
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Approach Traverse the array from left to right. For every element: If nums[i] > nums[i-1], no operation is needed. Otherwi…
Answer: EDUREKA Off-Campus Hiring OA (2024) | Problem Sum of Multiples
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Approach Traverse all numbers from 1 to n. For every number: If it is divisible by 3, 5, or 7, add it to the answer. Fin…
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Approach There are only two cases: If n is already even, then n itself is divisible by both 2 and n. If n is odd, multiply it by…
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Approach Instead of trying different starting values, observe that: We only need to know the minimum prefix sum encountered while …
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