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The 9th testcase for Problem 1 are probably wrong, seeing that problem author himself has incorrect solution. Here is an alternate solution…

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no you can move in any 4 directions it will cover only 2 directions left and down

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1. #include<bits/stdc++.h> using namespace std; void __solve() { int n, m; cin >> n >> m; vector&l…

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I guess we can also solve using tries. we will count the longest branch with consicutive end points.

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The TC of your algorithm is exponential as we end up adding n^(m) elements to the queue

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@admin can you tell how can one get premium for TJO?

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code you provide a code for this :)

Answer: AQR, Recent Online Assessment Questions (30th August 2023) | Program to accept ( by Ignotus2614 • 0

from collections import deque dx = [1, 1, -1, -1] dy = [-1, 1, 1, -1] def read_input(): n = int(input()) vec …

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Bro, I found it. the test case's expected output is wrong try changing the condition of when 2 heros occur at same coordinate (p1 occur…

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